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btrfs-progs: corrupt-block: Correctly handle -r when passing -I 

The documentation for the -I option (corrupt an item) states:

  An item to corrupt (must also specify the field to corrupt and a root+key for the item)

The code on the other hand doesn't check whether -r is in fact passed,
and even if it is it's not handled at all. This means presently -I
is possible to corrupt items only in the root tree. Fix this by
correctly checking -r is passed and fail otherwise and passing the
correct root to corrupt_btrfs_item.

Signed-off-by: Nikolay Borisov <nborisov@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
master
Nikolay Borisov 2018-05-14 14:13:27 +03:00 committed by David Sterba
parent 12087e6d75
commit 04be0e4b19
1 changed files with 7 additions and 1 deletions
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8
btrfs-corrupt-block.c
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@ -1337,9 +1337,15 @@ int main(int argc, char **argv)
goto out_close;
}
if (corrupt_item) {
struct btrfs_root *target;
if (!key.objectid)
print_usage(1);
ret = corrupt_btrfs_item(root, &key, field);
if (!root_objectid)
print_usage(1);
target = open_root(root->fs_info, root_objectid);
ret = corrupt_btrfs_item(target, &key, field);
}
if (delete) {
struct btrfs_root *target = root;